Optimal. Leaf size=175 \[ -2 d^{11/2} \left (b^2-4 a c\right )^{9/4} \tan ^{-1}\left (\frac{\sqrt{d (b+2 c x)}}{\sqrt{d} \sqrt [4]{b^2-4 a c}}\right )-2 d^{11/2} \left (b^2-4 a c\right )^{9/4} \tanh ^{-1}\left (\frac{\sqrt{d (b+2 c x)}}{\sqrt{d} \sqrt [4]{b^2-4 a c}}\right )+4 d^5 \left (b^2-4 a c\right )^2 \sqrt{b d+2 c d x}+\frac{4}{5} d^3 \left (b^2-4 a c\right ) (b d+2 c d x)^{5/2}+\frac{4}{9} d (b d+2 c d x)^{9/2} \]
[Out]
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Rubi [A] time = 0.487556, antiderivative size = 175, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 6, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.231 \[ -2 d^{11/2} \left (b^2-4 a c\right )^{9/4} \tan ^{-1}\left (\frac{\sqrt{d (b+2 c x)}}{\sqrt{d} \sqrt [4]{b^2-4 a c}}\right )-2 d^{11/2} \left (b^2-4 a c\right )^{9/4} \tanh ^{-1}\left (\frac{\sqrt{d (b+2 c x)}}{\sqrt{d} \sqrt [4]{b^2-4 a c}}\right )+4 d^5 \left (b^2-4 a c\right )^2 \sqrt{b d+2 c d x}+\frac{4}{5} d^3 \left (b^2-4 a c\right ) (b d+2 c d x)^{5/2}+\frac{4}{9} d (b d+2 c d x)^{9/2} \]
Antiderivative was successfully verified.
[In] Int[(b*d + 2*c*d*x)^(11/2)/(a + b*x + c*x^2),x]
[Out]
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Rubi in Sympy [A] time = 95.7899, size = 177, normalized size = 1.01 \[ - 2 d^{\frac{11}{2}} \left (- 4 a c + b^{2}\right )^{\frac{9}{4}} \operatorname{atan}{\left (\frac{\sqrt{b d + 2 c d x}}{\sqrt{d} \sqrt [4]{- 4 a c + b^{2}}} \right )} - 2 d^{\frac{11}{2}} \left (- 4 a c + b^{2}\right )^{\frac{9}{4}} \operatorname{atanh}{\left (\frac{\sqrt{b d + 2 c d x}}{\sqrt{d} \sqrt [4]{- 4 a c + b^{2}}} \right )} + 4 d^{5} \left (- 4 a c + b^{2}\right )^{2} \sqrt{b d + 2 c d x} + \frac{4 d^{3} \left (- 4 a c + b^{2}\right ) \left (b d + 2 c d x\right )^{\frac{5}{2}}}{5} + \frac{4 d \left (b d + 2 c d x\right )^{\frac{9}{2}}}{9} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((2*c*d*x+b*d)**(11/2)/(c*x**2+b*x+a),x)
[Out]
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Mathematica [A] time = 0.431725, size = 190, normalized size = 1.09 \[ \frac{2 d^5 \sqrt{d (b+2 c x)} \left (2 \sqrt{b+2 c x} \left (16 c^2 \left (45 a^2-9 a c x^2+5 c^2 x^4\right )+12 b^2 c \left (13 c x^2-33 a\right )+16 b c^2 x \left (10 c x^2-9 a\right )+59 b^4+76 b^3 c x\right )-45 \left (b^2-4 a c\right )^{9/4} \tan ^{-1}\left (\frac{\sqrt{b+2 c x}}{\sqrt [4]{b^2-4 a c}}\right )-45 \left (b^2-4 a c\right )^{9/4} \tanh ^{-1}\left (\frac{\sqrt{b+2 c x}}{\sqrt [4]{b^2-4 a c}}\right )\right )}{45 \sqrt{b+2 c x}} \]
Antiderivative was successfully verified.
[In] Integrate[(b*d + 2*c*d*x)^(11/2)/(a + b*x + c*x^2),x]
[Out]
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Maple [B] time = 0.027, size = 1287, normalized size = 7.4 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((2*c*d*x+b*d)^(11/2)/(c*x^2+b*x+a),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((2*c*d*x + b*d)^(11/2)/(c*x^2 + b*x + a),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.244869, size = 1401, normalized size = 8.01 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((2*c*d*x + b*d)^(11/2)/(c*x^2 + b*x + a),x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((2*c*d*x+b*d)**(11/2)/(c*x**2+b*x+a),x)
[Out]
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GIAC/XCAS [A] time = 0.263549, size = 779, normalized size = 4.45 \[ 4 \, \sqrt{2 \, c d x + b d} b^{4} d^{5} - 32 \, \sqrt{2 \, c d x + b d} a b^{2} c d^{5} + 64 \, \sqrt{2 \, c d x + b d} a^{2} c^{2} d^{5} + \frac{4}{5} \,{\left (2 \, c d x + b d\right )}^{\frac{5}{2}} b^{2} d^{3} - \frac{16}{5} \,{\left (2 \, c d x + b d\right )}^{\frac{5}{2}} a c d^{3} + \frac{4}{9} \,{\left (2 \, c d x + b d\right )}^{\frac{9}{2}} d - \frac{1}{2} \, \sqrt{2}{\left (b^{4} d^{5} - 8 \, a b^{2} c d^{5} + 16 \, a^{2} c^{2} d^{5}\right )}{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{1}{4}}{\rm ln}\left (2 \, c d x + b d + \sqrt{2}{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{1}{4}} \sqrt{2 \, c d x + b d} + \sqrt{-b^{2} d^{2} + 4 \, a c d^{2}}\right ) + \frac{1}{2} \, \sqrt{2}{\left (b^{4} d^{5} - 8 \, a b^{2} c d^{5} + 16 \, a^{2} c^{2} d^{5}\right )}{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{1}{4}}{\rm ln}\left (2 \, c d x + b d - \sqrt{2}{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{1}{4}} \sqrt{2 \, c d x + b d} + \sqrt{-b^{2} d^{2} + 4 \, a c d^{2}}\right ) -{\left (\sqrt{2} b^{4} d^{5} - 8 \, \sqrt{2} a b^{2} c d^{5} + 16 \, \sqrt{2} a^{2} c^{2} d^{5}\right )}{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{1}{4}} \arctan \left (\frac{\sqrt{2}{\left (\sqrt{2}{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{1}{4}} + 2 \, \sqrt{2 \, c d x + b d}\right )}}{2 \,{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{1}{4}}}\right ) -{\left (\sqrt{2} b^{4} d^{5} - 8 \, \sqrt{2} a b^{2} c d^{5} + 16 \, \sqrt{2} a^{2} c^{2} d^{5}\right )}{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{1}{4}} \arctan \left (-\frac{\sqrt{2}{\left (\sqrt{2}{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{1}{4}} - 2 \, \sqrt{2 \, c d x + b d}\right )}}{2 \,{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{1}{4}}}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((2*c*d*x + b*d)^(11/2)/(c*x^2 + b*x + a),x, algorithm="giac")
[Out]